Tse Wu

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since Jan 05, 2012
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Recent posts by Tse Wu

Think about it this way, if you have an animal class and a dog and cat class that extends animal. And you have a method that accepts <? extends animal>, this is saying you could pass anything that is a subclass of the class animal into this method. Now say that you have a dog collection and you pass that dog collection into the method, and in that method you try and add a cat.. now you have a collection of dogs and cats in the dog collection. To prevent this the compiler will not allow adding to the collection using the extend keyword.
Thanks all.

Glen Iris wrote:Congratulations Tse Wu.

How many practice exams did you complete before taking the test?

What sort of scores were you getting on your last few practice exams?



I took both practice exams in the book, first time I scored a 55 and the second time was 60. I didn't do the timed test and took my time to solve the issues. From what I have gathered if you scored about this range passing shouldn't be a problem. I also started on the supplemental practice exam book but never got far with it since I ran out of time to prepare. Let me know if you need help on the topics.
12 years ago
I think it is a safe bet that you are better off reading the entire K&B book, the only thing that was not on the exam for me was serialization.
Just passed the exam despite of leaving 5 questions unanswered due to lack of time. Got a 73, I think I could've gotten higher but I am glad to score above 61.

The exam itself was less complex compared to the K&B practice exams, I think because the way I took these practice exams I reviewed simple answers 3 or 4 times before moving on. That killed most of the time for me in retrospec. The takeaway for me was studying the practice exam questions, other than memorizing APIs and rules. I didn't encounter any serialization questions like everyone said, and I came across more .io questions than i would've liked. And the questions went from simple to hard instead of a random mix. Hope this helps.
12 years ago
Hi Matt,
From my understanding.

Step1: Since the first y is post decrement, the first y value is 1.
Step2: After the resolution of the first y, y is decreased to 0.
Step3: The second y is also post decrement, so the second y value is assigned to 0.
Step4: after the resolution of the second y, y is decreased to -1.
Step5: so we ended up with 1 + 0
Step6: At this point y is -1, but since 1 + 0 is 1 the assignment of y changed from -1 to 1 at this point.

I think this is how it goes with the explanation you provided which made sense. Let me know if one of the steps was wrong. Thanks again.
Thanks Matt.
Y ended up not being -1 due to the fact that the final value was assigned as the sum of the expression. Essentially y was -1 before being reassigned to 1.. Do I have the jist of it?
Hi, why is the following 1?

int y = 1;
y = y-- + y--;

Thanks.
Hi Mallik,
It should be

new SameRun().run("Overloaded");
"This class implements the Set interface, backed by a hash table (actually a HashMap instance). It makes no guarantees as to the iteration order of the set; in particular, it does not guarantee that the order will remain constant over time. This class permits the null element."

http://docs.oracle.com/javase/6/docs/api/java/util/HashSet.html


I think the key to understand this concept is knowing the difference between sorted and ordered. HashSet is unsorted and unordered.
Hi,
I think it should be the following

public void checkAnimals(List<? extends Animal> animals)

Since passing List is a type of <Dog>, <Cat> or <Bird> you cannot pass the <Dog> type into an <Animal> type directly other than extending it with ?.