Ana P

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since May 02, 2002
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Recent posts by Ana P

how can in while loop b++ calculates -128
binary value of 127 is
0111 1111
+ 1
1000 0000
pls explain...
byte b1 = 1;
while ( ++b1 > 0 );
System.out.println(b1); //prints -128 ???
System.out.println("Welcome to My World!");
[ May 15, 2002: Message edited by: Ana P ]
Thx this does help.
I just wnat to make sure that string literals are not garbage collected
see this site
last q says that string literal is eligible for garbage collection
public class GCTest {
public static void main(String args[]) {
String a,b;
String c = "test";
a = c;
c = null; // The String "test" is not yet
//available for GC as a still points to "test"
b = new String("xyz");
b = c; // String "xyz" is now available for GC.
a = null; //String "test" is now available for GC.
a = null; //String "test" is now available for GC.
I think string literal are not garbage collected
double d21=10.3;
float f21=10.3f;
System.out.println("d==f " + (f21==d21));
This does not return true for all values
like 0.9. 0.5
I think while promotion it loses precision.
am i right?
char ch = '1' + '8';
System.out.println("ch= " + ch); // prints i
char ch2='2';
char ch3='1';
ch3 += ch2;
System.out.println("ch3= " + ch); // this also prints i
why so?
double d=0.9;
float f=0.9f;
System.out.println("d==f " + (d==f));
I tried this , but got answer d==f as false
n a Java program, if the Unicode escape sequence \u000A, for example, occurs within a single-line comment, it is interpreted as a line terminator (Unicode character 000A is line feed) and therefore the next character is not part of the comment.
Similarly, if the Unicode escape sequence \u000A occurs within a string literal in a Java program, it is likewise interpreted as a line terminator, which is not allowed within a string literal.
One must write \n instead of \u000A to cause a line feed to be part of the string value of a string literal.
Because Unicode escapes are processed very early, it is not correct to write '\u000a' for a character literal whose value is linefeed (LF); the Unicode escape \u000a is transformed into an actual linefeed and the linefeed becomes a LineTerminator, and so the character literal is not valid. Instead, one should use the escape sequence '\n. Similarly, it is not correct to write '\u000d' for a character literal whose value is carriage return (CR). Instead, use '\r'.
Look at this example...
class Super{
public Super() //1
void a() //1
void method() //3
public class Subclass1 extends Super{
public Subclass1()//4
public void method() //5
public static void main(String []args) {
Super c = new Subclass1(); // 4 - 1 - 3

The output of this prog is 2 2
I thought it should be 1 2
how this works?
Super c = new Subclass1(); // 4 - 1 - 3
after this line control will go to super class constructor. and then method a() at 1 and then call to method at 3. but it does not work that way
pls explain...
Hi June,
Heartly congrats.
Pls do share ur exp. with us.
19 years ago
I am really confused about garbage collection mechanism of string objects. Can anyone help me on this topic.
I read it somewhere that
String objects created like :
String a="abc" will not be garbage collected
while String a= new String("abc") will get gc' ted.
String a,b,c;
then how many objects will get garbage collected and when?