Jai007

If the purpose of synchronization is to provide controlled serialised access by different threads(correct me if I am wrong)then what is the logic of the following restriction:
&&&
Variables and classes cannot be synchronized. Any code block within a method can be synchronized by enclosing it in {}.

Can somebody help me understanding the following outcome!!
&&&
public class Test {
public static void main(String args[]) {
StringBuffer a = new StringBuffer("One");
StringBuffer b = new StringBuffer("Two");
Test.swap(a,b);
System.out.println("a is "+ a +"\nb is " + b);
}
static void swap (StringBuffer a, StringBuffer b) {
a.append(" more");
b=a;
}
}
What will be the output?
Answer:
d. a is One more
b is Two

what does (i==1 &| j==2) means!!

Difference between keywords or reserved words in Java?

Help me understand the following logic:
&&&&
TextField t = new TextArea("12345", 5, 5);
why following statement is false?
C. The maximum number of characters in a line will be five.

In view of Answers to 108 & 23 how can answer to 3 can be still true:
&&&
Answer to Question 108
1)
char c='1';
System.out.println(c>>1);
The fact that option 1 will compile may be a surprise, but although the char type is normally used to store character types, it is actually an unsigned integer type. The reason option 3 does not compile is that Java has a >>> operator but not a <<< operator.
Will NOT compile.
Answer to uestion 23)
2)s+=i;
Only a String acts as if the + operator were overloaded
Answer to Question 3)
2) int i=2+'2';
3) String s="on"+'one';
Option 3 is not valid because single quotes are used to indicate a character constant and not a string. Several people have emailed me to say that option 3 will compile. When they eventually compiled the exact code they have agreed, it will not compile.