Brian Jones Jr.

is Secrets of the JavaScript Ninja 2nd Edition out of date

Hi, I was thinking about reading this book after reading a beginners book on JS. Is this book outdated, or is it still a good read in 2022? Is a 3rd edition coming out soon? I'm going to use JS for front end web development. I did a quick google search and I didn't see any recent reviews from the last year on code ranch or reddit. Thanks.

3 years ago

Tim Moores wrote:For additional ideas you could also study the source code of a mature Java blog platform such as http://pebble.sourceforge.net/. It supports multiple blogs as well as multiple contributors per blog.

Thanks! That's super helpful.

7 years ago

Stephan van Hulst wrote:I believe Wildfly just uses the standard Java EE security mechanisms. You can read more about those here: https://docs.oracle.com/javaee/7/tutorial/partsecurity.htm

I believe chapter 47 will explain how to add users, groups and roles to your application, and chapter 49 will explain how to authorize certain users, groups or roles to access methods in your application.

Thanks! I heard of this, but I wasn't sure exactly what it did.

7 years ago

Stephan van Hulst wrote:Typically this is done by middleware in the request processing pipeline of your web application framework. Most web application frameworks have already implemented this middleware. For instance, Spring has the Spring Security project which includes in-memory authentication.

What framework are you using to develop your web application?

Thanks. I don't think I have a framework equivalent to Spring. This is some of my tech stack:

Wildfly 10
Hibernate 5
Postgres 9
Weld
RESTEasy JaxRS
AngularJS 1
Java 8

Can I add only Spring Security to my project?

7 years ago

I also don't have the database setup. So, I also need a temporary way to do this. Thanks.

7 years ago

I am building a java web app. It will be a blog. I need to add login functionality so that an authorized user can create a blog, and it will prevent an unauthorized user from accessing the blog creation features. How would this be implemented on an Enterprise app? Thanks.

7 years ago

Unable to build entity manager factory

Rob Spoor wrote:Ignore any JBoss/WildFly specific configuration. You're trying to run a unit test, and that has (more or less) the same rules as a standalone JSE application.

Last time I had to unit test my database code, I simply used a second persistence.xml (in src/test/resources/META-INF) with its own persistence unit name, and used that. This one was mostly identical, except:
1) the transaction-type was RESOURCE_LOCAL instead of JTA.
2) there was no data source, but properties for connecting instead (you already have those).
3) classes were included instead of relying on automatic discovery.

Thanks! I'll give this a try.

7 years ago

Object Relational Mapping

Unable to build entity manager factory

My stack:
JBoss Wildfly 10 server
Ubuntu 16.04
Java 8
Postgres 9.5.6
Hibernate 5

I am having problems trying to get my JUnit test to work. The unit tests were created by JBoss and they are used to test if Hibernate is working properly. I got their hibernate5 quickstart tutorial to work, and it was using an H2 database. Now I'm trying to using some of their code (datasource.xml and persistence.xml) for my personal project, and I'm using a Postgres database with Hibernate JPA. I got the following exception when I tried to run the unit test:

@BeforeClass - runOnceBeforeClass
Problem creating factory
javax.persistence.PersistenceException: Unable to build entity manager factory
at org.hibernate.jpa.HibernatePersistenceProvider.createEntityManagerFactory(HibernatePersistenceProvider.java:66)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:55)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:39)
at com.bernales.test.TestEntityManager.runOnceBeforeClass(TestEntityManager.java:34)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:50)
at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:12)
at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:47)
at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:24)
at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:27)
at org.junit.runners.ParentRunner.run(ParentRunner.java:363)
at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:86)
at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:459)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:678)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:382)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:192)
Caused by: org.hibernate.service.spi.ServiceException: Unable to create requested service [org.hibernate.engine.jdbc.env.spi.JdbcEnvironment]
at org.hibernate.service.internal.AbstractServiceRegistryImpl.createService(AbstractServiceRegistryImpl.java:264)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.initializeService(AbstractServiceRegistryImpl.java:228)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.getService(AbstractServiceRegistryImpl.java:207)
at org.hibernate.engine.jdbc.internal.JdbcServicesImpl.configure(JdbcServicesImpl.java:51)
at org.hibernate.boot.registry.internal.StandardServiceRegistryImpl.configureService(StandardServiceRegistryImpl.java:94)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.initializeService(AbstractServiceRegistryImpl.java:237)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.getService(AbstractServiceRegistryImpl.java:207)
at org.hibernate.boot.model.process.spi.MetadataBuildingProcess.handleTypes(MetadataBuildingProcess.java:352)
at org.hibernate.boot.model.process.spi.MetadataBuildingProcess.complete(MetadataBuildingProcess.java:111)
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.metadata(EntityManagerFactoryBuilderImpl.java:847)
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:874)
at org.hibernate.jpa.HibernatePersistenceProvider.createEntityManagerFactory(HibernatePersistenceProvider.java:58)
... 19 more
Caused by: org.hibernate.engine.jndi.JndiException: Error parsing JNDI name [java:jboss/datasources/HibernateMyAppDS]
at org.hibernate.engine.jndi.internal.JndiServiceImpl.parseName(JndiServiceImpl.java:124)
at org.hibernate.engine.jndi.internal.JndiServiceImpl.locate(JndiServiceImpl.java:95)
at org.hibernate.engine.jdbc.connections.internal.DatasourceConnectionProviderImpl.configure(DatasourceConnectionProviderImpl.java:98)
at org.hibernate.boot.registry.internal.StandardServiceRegistryImpl.configureService(StandardServiceRegistryImpl.java:94)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.initializeService(AbstractServiceRegistryImpl.java:237)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.getService(AbstractServiceRegistryImpl.java:207)
at org.hibernate.engine.jdbc.env.internal.JdbcEnvironmentInitiator.buildJdbcConnectionAccess(JdbcEnvironmentInitiator.java:145)
at org.hibernate.engine.jdbc.env.internal.JdbcEnvironmentInitiator.initiateService(JdbcEnvironmentInitiator.java:66)
at org.hibernate.engine.jdbc.env.internal.JdbcEnvironmentInitiator.initiateService(JdbcEnvironmentInitiator.java:35)
at org.hibernate.boot.registry.internal.StandardServiceRegistryImpl.initiateService(StandardServiceRegistryImpl.java:88)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.createService(AbstractServiceRegistryImpl.java:254)
... 30 more
Caused by: javax.naming.NoInitialContextException: Need to specify class name in environment or system property, or as an applet parameter, or in an application resource file:  java.naming.factory.initial
at javax.naming.spi.NamingManager.getInitialContext(NamingManager.java:662)
at javax.naming.InitialContext.getDefaultInitCtx(InitialContext.java:313)
at javax.naming.InitialContext.getURLOrDefaultInitCtx(InitialContext.java:350)
at javax.naming.InitialContext.getNameParser(InitialContext.java:505)
at org.hibernate.engine.jndi.internal.JndiServiceImpl.parseName(JndiServiceImpl.java:118)
... 40 more

Here's the unit test method that corresponds with the exception. The exception is thrown in the try block:

package com.bernales.test;
import static org.junit.Assert.assertTrue;
import java.util.List;
import javax.persistence.EntityManager;
import javax.persistence.EntityManagerFactory;
import javax.persistence.Persistence;
import org.junit.After;
import org.junit.AfterClass;
import org.junit.Before;
import org.junit.BeforeClass;
import org.junit.Test;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import com.bernales.model.Person;
public class TestEntityManager {
final Logger logger = LoggerFactory.getLogger(TestEntityManager.class);
private static EntityManagerFactory entityManagerFactory;
private static EntityManager entityManager;
// Run once, e.g. Database connection, connection pool
@BeforeClass
public static void runOnceBeforeClass() {
System.out.println("@BeforeClass - runOnceBeforeClass");
try {
entityManagerFactory = Persistence.createEntityManagerFactory("primary");
} catch (Exception exception) {
System.out.println("Problem creating factory");
exception.printStackTrace();
System.out.println("");
}
}
...
}
}

I tried to configure my standalone.xml using this StackOverflow post webpage. Here's what my standalone.xml datasource looks like:

<datasources>
<datasource jta="false" jndi-name="java:jboss/datasources/HibernateMyAppDS" pool-name="myappds" enabled="true" use-ccm="false">
       <connection-url>jdbc:postgresql://localhost:5432/postgres</connection-url>
       <driver>postgres</driver>
               <security>
               <user-name>postgres</user-name>
        <password>postgres</password>
       </security>
     <validation>
        <validate-on-match>false</validate-on-match>
        <background-validation>false</background-validation>
       </validation>
       <statement>
        <share-prepared-statements>false</share-prepared-statements>
       </statement>
</datasource>
<drivers>
       <driver name="postgres" module="org.postgres">
               <driver-class>org.postgresql.Driver</driver-class>
       </driver>
</drivers>              

</datasources>

Here's what my module.xml looks like. It's in directory wildfly-10.1.0.final/modules/org/postgres/main:

Here's what my datasource in the WEB-INF folder looks like:

Here's what my persistence.xml looks like from the META-INF folder:

<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1"
xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
       http://xmlns.jcp.org/xml/ns/persistence
       http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="primary">
<provider>org.hibernate.ejb.HibernatePersistence</provider>

<jta-data-source>java:jboss/datasources/HibernateMyAppDS</jta-data-source>

<class>com.bernales.model.Person</class>
<properties>

<property name="hibernate.archive.autodetection" value="class" />
<property name="hibernate.dialect" value="org.hibernate.dialect.PostgreSQLDialect" />
<property name="hibernate.hbm2ddl.auto" value="create" />
<property name="hibernate.connection.driver_class" value="org.postgresql.Driver" />
<property name="hibernate.connection.username" value="postgres" />
<property name="hibernate.connection.password" value="postgres" />
<property name="hibernate.connection.url" value="jdbc:postgresql://localhost:5432/postgres" />
</properties>
</persistence-unit>
</persistence>

Does anyone know what I need to do in order to fix this exception? Thanks.

7 years ago

Object Relational Mapping

confused by javascript/angular code operator ||

I tested the following code in in JSFiddle, and it returned 0. Why is this not returning false?

7 years ago

confused by javascript/angular code operator ||

I'm trying to work through the AngularJS v1.2 tutorial. The task is to:

Add a method to GalleryController called setCurrent that accepts a value and assigns it to current. If no value is passed in, set current to 0.

The pertinent code in app.js

Here's the index.html that uses that GalleryController

<!DOCTYPE html>
<html ng-app="gemStore">
 <head>
   <link rel="stylesheet" type="text/css" href="bootstrap.min.css" />
   <script type="text/javascript" src="angular.min.js"></script>
   <script type="text/javascript" src="app.js"></script>
 </head>
 <body class="list-group" ng-controller="StoreController as store">
   <header>
     <h1 class="text-center">Flatlander Crafted Gems</h1>
     <h2 class="text-center">– an Angular store –</h2>
   </header>
   <div class="list-group-item" ng-repeat="product in store.products">
     <h3>
       {{product.name}}
       <em class="pull-right">{{product.price | currency}}</em>
     </h3>
     
     <div class='gallery' ng-controller="GalleryController as gallery"  ng-show="product.images.length">
       <div class="img-wrap">
         <img ng-src="{{product.images[gallery.current]}}" />
       </div>
       <ul class="img-thumbnails clearfix">
         <li class="small-image pull-left thumbnail" ng-repeat="image in product.images">
           <img ng-src="{{image}}" />
         </li>
       </ul>
     </div>
     <section class="tab" ng-controller="TabController as tab">
       <ul class="nav nav-pills">
         <li ng-class="{ active: tab.isSet(1) }">
           <a href ng-click="tab.setTab(1)">Description</a></li>
         <li ng-class="{ active: tab.isSet(2) }">
           <a href ng-click="tab.setTab(2)">Specs</a></li>
         <li ng-class="{ active: tab.isSet(3) }">
           <a href ng-click="tab.setTab(3)">Reviews</a></li>
       </ul>
       <div ng-show="tab.isSet(1)">
         <h4>Description</h4>
         <blockquote>{{product.description}}</blockquote>
       </div>
       <div ng-show="tab.isSet(2)">
         <h4>Specs</h4>
         <blockquote>Shine: {{product.shine}}</blockquote>
       </div>
       <div ng-show="tab.isSet(3)">
         <h4>Reviews</h4>
       </div>
     </section>
   </div>
 </body>
</html>

I don't understand how || works on line 8. According to the MDN docs for Logical Operators I think this should set this.current to false if nothing is passed into it. I am confused. Can someone help me? Thanks.

7 years ago