Sibi Varghese

Using Selenium/Java I was able to do ALL 10 steps required in the assignment file: S2_Assign1.JPG
but, I'm not able validate the deposit I added manually on the website as seem in file: VD.
For some reason the code is return with below error



package test; import java.util.concurrent.TimeUnit; import org.junit.Test; import org.openqa.selenium.By; import org.openqa.selenium.WebDriver; import org.openqa.selenium.chrome.ChromeDriver; import org.openqa.selenium.support.ui.ExpectedConditions; import org.openqa.selenium.support.ui.Wait; import org.openqa.selenium.support.ui.WebDriverWait; import junit.framework.Assert; public class ValidateDeposit { @Test    public void validateDepositWasPosted()throws InterruptedException {       System.setProperty("webdriver.chrome.driver","./driver/chromedriver.exe");   WebDriver driver = new ChromeDriver();                     driver.get("http://techfios.com/test/billing/?ng=admin/");           driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);           driver.findElement(By.xpath("//*[@type='text']")).sendKeys("techfiosdemo@gmail.com");           driver.findElement(By.xpath("//input[@type='password']")).sendKeys("abc123");           //driver.findElement(By.xpath("//*[contains(@placeholder, 'assword') and contains(@class, 'form-')]")).sendKeys("abc123");           driver.findElement(By.xpath("//button[@type ='submit']")).click();           //driver.findElement(By.xpath("//button[contains(text(), 'Sign in') and @name='login'] ")).click();                     driver.findElement(By.xpath("//li[3]/a/span[@class='nav-label']")).click();           driver.findElement(By.xpath("//li[3]/ul/li[1]/a")).click();           //driver.findElement(By.xpath("//*[@id=\"select2-acco//unt-container\"]")).click();           //driver.findElement(By.xpath("//*[@id="account"]/option[507]")).click();           driver.findElement(By.xpath("//option[@value='HomeLoan#2020']")).click();           Thread.sleep(3000);           driver.findElement(By.xpath("//input[@name='description']")).sendKeys("NHB7582");           driver.findElement(By.xpath("//input[@id='amount']")).sendKeys("15000");           driver.findElement(By.xpath("//button[@type='submit']")).click();             //String depositValidator = "//a[contians(text(), 'New Home Buyer')]";           String depositValidator = "//*[@id=\"page-wrapper\"]/div[3]/div[1]/div[2]/div/div[2]/table/tbody/tr[1]/td[1]/a, 'NHB7582')]";                     WebDriverWait wait = new WebDriverWait(driver, 10);           wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath(depositValidator)));           String expectedText = "NHB7582";             //String actualText = driver.findElement(By.xpath("//a[contians(text(), 'New Home Buyer')]")).getText();           String actualText = driver.findElement(By.xpath("//*[@id=\"page-wrapper\"]/div[3]/div[1]/div[2]/div/div[2]/table/tbody/tr[1]/td[1]/a, 'NHB7582')]")).getText();                      Assert.assertEquals("Deposit did not display", expectedText, actualText);            driver.close();            driver.quit();     } } [code=java]Failure Trace [code=java]org.openqa.selenium.TimeoutException: Expected condition failed: waiting for visibility of element located by By.xpath: //*[@id="page-wrapper"]/div[3]/div[1]/div[2]/div/div[2]/table/tbody/tr[1]/td[1]/a, 'NHB7582')] (tried for 10 second(s) with 500 milliseconds interval)

I was able to fix the Java 8 issue by configuring each project by right clicking and
selecting Build Path/Configure Build Path. Then under Libraries had to change Modulepath
to JavaSE-18 and Classpath select jdk 1.8.0_221. I hope no other issue I will face while
working with Selenium since, I have Java 8 configured

I had JDK 13 but, I downgraded to JDK 8 and also installed the prequisites from the this website: http://autotechnotes.weebly.com/prereq.html

then, Set Environment Variables as show on the weebly website for Java 8 (JDK8)

As per previous screenshot file name : RandomNumberNth.java

Below are some errors underlined in 'RED'
*************************************
import java.util.Random; public class RandomNumeberNth { public static void main(String[] args)

Line 1 : java.util

Error: The import java.util can not be resolved


Line 2 : RandomNumeberNth

Error: Implicit super constructor Object() is undefined for default constructor. Must define an explicit constructor.


Line 3 : String

Error: String cannot be resolved to a type

*************************************
Error on Line 1
[Random rnum = new Random()]
underlined in red  'Random'
error : Random cannot be resolved to a type.  



As I said earlier when I installed JDK 13 back on the Java projects worked perfectly with no errors unlike Java 8 (JDK 8).

Someone told me to reconfigure the run configuration and choose java 8 not sure about it but, I see run configuration under 'Run' tab.

Let me know if there a way fix this issue unable to run Java projects on JDK 8.

JDK 8 was installed and uninstalled latest version JDK 13 to work on Selenium.
But, I was unable runs any Java Projects as you can see the screenshot.
The issue was resolved after reinstalling the latest JDK 13 again but,
by keeping both JDK 8 and JDK 13 it will cause issues with running Selenium down the road
so, is there a solution to this issue to get fix for using JDK 8 for both Java and Selenium.

This code is to print duplicate character of a given String.
What does the logic behind these lines of code. Why there are two 'if' statements :                                

if (!duplicates.contains(String.valueOf(str.charAt(j)))) {
                           duplicates += str.charAt(j);
Can someone please explain lines 18 and 19?    

@Knute Snortum          
         int startcounter=100;  // Do I keep startcounter on '0' if I have generate 500 random numbers
   int n=0; // This is initial value of n and later it incremented as n++ and initialized as variable 'c'
 int endCounter=500;
 int arraysize = endCounter-startcounter; // this defines the array size, basically of 500 random numbers  
 int numbers[] = new int[arraysize+1]; Declaring integer array for variable 'numbers' equal to new integer[size of array +1]

Please correct my understanding. Thanks in advance.

Sibi Varghese wrote:Awesome!!! Knute Snortum. Thanks a lot.

Knute Snortum wrote:You've already been told to UseCodeTags (that's a link) when you post code.

1)  int endCounter=500; - Do I keep this 500 since, I'm generating 500 numbers

Yes.  

2)  this part of the code :
        int c = n++;
int num = rnum.nextInt(1000);
numbers[c]= num;

Some confusion with these lines of code : 1) basically you are declaring int variable 'c' and the value is incremented as n++ 2) Generates integer to be printed and return a number within > =1000 - int num = rnum.nextInt(1000); 3) numbers[c]= num; creating a array and assigning to num. Please correct my understanding.

1) Not quite.  Since the ++ is after the variable name, you use the variable first, then increment it.  So c gets n than n get incremented.

2) Almost.  nextInt(1000) will create an integer from 0 to 999.

3) No.  The array numbers has already be defined.  numbers[c]= num; assigns num to numbers at index c.

Awesome!!! Knute Snortum. Thanks a lot.

Knute Snortum wrote:You've already been told to UseCodeTags (that's a link) when you post code.

1)  int endCounter=500; - Do I keep this 500 since, I'm generating 500 numbers

Yes.  

2)  this part of the code :
        int c = n++;
int num = rnum.nextInt(1000);
numbers[c]= num;

Some confusion with these lines of code : 1) basically you are declaring int variable 'c' and the value is incremented as n++ 2) Generates integer to be printed and return a number within > =1000 - int num = rnum.nextInt(1000); 3) numbers[c]= num; creating a array and assigning to num. Please correct my understanding.

1) Not quite.  Since the ++ is after the variable name, you use the variable first, then increment it.  So c gets n than n get incremented.

2) Almost.  nextInt(1000) will create an integer from 0 to 999.

3) No.  The array numbers has already be defined.  numbers[c]= num; assigns num to numbers at index c.

This code I got worked out from someone online:

import java.util.Random;
public class RandomNumeberNth {

 public static void main(String[] args) {

 int startcounter=100;
 int n=0;
 int endCounter=500;
 int arraysize = endCounter-startcounter;
 int numbers[] = new int[arraysize+1];
 Random rnum = new Random();
 System.out.println("Random Numbers\n****************");
     for(int counter=startcounter;counter<=endCounter;counter++)
 {
 int c = n++;
 int num = rnum.nextInt(1000);
 numbers[c]= num;
 System.out.println(numbers[c]);

 }
 int smallest = numbers[0];
               int biggest = numbers[0];

               for(int i=1; i< numbers.length; i++)
               {
                       if(numbers[i] > biggest)
                               biggest = numbers[i];
                       else if (numbers[i] < smallest)
                               smallest = numbers[i];
               }
               System.out.println("Largest Number is : " + biggest);
               System.out.println("Smallest Number is : " + smallest);
}
}

so, I had few questions on some lines of code

1)  int endCounter=500; - Do I keep this 500 since, I'm generating 500 numbers

2)  this part of the code :
         int c = n++;
 int num = rnum.nextInt(1000);
 numbers[c]= num;

Some confusion with these lines of code : 1) basically you are declaring int variable 'c' and the value is incremented as n++ 2) Generates integer to be printed and return a number within > =1000 - int num = rnum.nextInt(1000); 3) numbers[c]= num; creating a array and assigning to num. Please correct my understanding.

1) Generate 500 Random number range from 100 – 1000

import java.util.Random; public class RandomNumbers {   public static void main(String[] args) {      int counter;      Random rnum = new Random();      /* Below code would generate 500 random numbers       * between 100 and 1000.       */      System.out.println("Random Numbers:");      System.out.println("***************");      for (counter = 100; counter <= 500; counter++) {         System.out.println(rnum.nextInt(1000));      }   } }

2) Nth smallest number

import java.util.Arrays; public class Nthsmall { public static void main(String[] args) { int numbers [] = {10, 15, 20, -88}; int largest = numbers[0]; int smallest = numbers[0]; for(int i = 1;  i<numbers.length; i++) {             if(numbers[i]>largest) {             largest = numbers[i];             }             else if(numbers[i]<smallest) {             smallest = numbers[i];             }  }       System.out.println("List of array is: " + Arrays.toString(numbers));       System.out.println("Largest numbers is : " +largest);       System.out.println("Smallest number is : " +smallest);    } }

How can I merge both into one code so, that after generating 500 random number b/w 100-1000, the next code should print the Nth smallest number.
Can someone please help me with the right logic to solve this.

Thanks